Question

Find the algebraic expression for the numbers got by adding 10 repeatedly to 1 11 21 31 41 51 61​

Answer 1

The algebraic expression  1+10x    [where x= 0,1,2....]

Step-by-step explanation:  

The algebraic expression  1+10x [where x= 0,1,2....]

Answer 2

The algebraic expression to the given numbers is  $10n+1$ for n=0,1,2,34,5,6 is true

Step-by-step explanation:

• Given numbers are 1,11,21,31,41,51,61
• To find the algebraic expression for the given numbers :
• Let the first term be 1 and second term be 11 etc
• The difference between the successive terms is 10
• Or if we add 10 to first term we get 11, add 10 to 11 we get 21,as so on
• Therefore the numbers can be written as $10n+1$ for n=0,1,2,34,5,6
• Now  verify that the expression is true or not
• put n=0 then $10(0)+1$=1
• put n=1 then $10(1)+1$=11
• put n=2 then $10(2)+1$=21
• put n=3 then $10(3)+1$=31
• put n=4 then $10(4)+1$=41
• put n=5 then $10(5)+1$=51
• put n=6 then $10(6)+1$=61
• Therefore the algebraic expression to the given numbers is  $10n+1$ for n=0,1,2,34,5,6 is true