Find the algebraic expression to express the following series.
62, 59, 56, 53.......
Answers
Answered by
3
answer : nth term of given series is 65 - 3n
given series ; 62 , 59 , 56 , 53 ......
first term , a = 62
common difference , d = 59 - 62 = 56 - 59 = 53 - 56 = -3 [ constant ]
it is clear that, series is in Arithmetic progression.
so, nth term of given series, Tn = a + (n - 1)d
= 62 + (n - 1)(-3)
= 62 - 3n + 3
= 65 - 3n
also read similar questions : Sum of three consecutive terms of an Arithmetic Progression is 42 and their product is 2520.
Find the terms of the Arit...
https://brainly.in/question/11255431
In the arithmetic progression, a8 = 5, a15 = -23. Find the difference in the progression.
https://brainly.in/question/1140414
Similar questions