Question

Find the algebraic expression to express the following series.
62, 59, 56, 53.......​

Answer 1

answer : nth term of given series is 65 - 3n

given series ; 62 , 59 , 56 , 53 ......

first term , a = 62

common difference , d = 59 - 62 = 56 - 59 = 53 - 56 = -3 [ constant ]

it is clear that, series is in Arithmetic progression.

so, nth term of given series, Tn = a + (n - 1)d

= 62 + (n - 1)(-3)

= 62 - 3n + 3

= 65 - 3n

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