Question

find the all zeroes of 2x⁴-3x³+6x is you know that two of its zeroes are √2 and -√2​

Answer 1

Step-by-step explanation:

The zeroes are

$\sqrt{2 \: } and \: - \sqrt{2} \: we \: can \: write \: it \: as \: (x - 2) \times (x + 2)$

(x-2)×(x+2)=x²- 2²=ײ‐4

Divide 2x⁴ ‐3x³+6x by x²‐4,then,

x²‐4)2x⁴ ‐3x³+0x²+6x+0(2x²‐3x+8

=2x²‐3x+8

Here,by factorization there are no roots for the polynomial