Find the all zeroes of f (x)=x power cube-2x
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Answered by
2
take x common
x(x.x-2)=0
x=0
then x= root 2
x(x.x-2)=0
x=0
then x= root 2
Answered by
2
f(x) = 0
x³-2x = 0
x(x²-2) = 0
x(x+2)(x-3) = 0
=> x = 0, -2,3
Zeroes of f(x) are 0, -2,3
x³-2x = 0
x(x²-2) = 0
x(x+2)(x-3) = 0
=> x = 0, -2,3
Zeroes of f(x) are 0, -2,3
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