Question

Find the all zeros of x4 - 3x3 +6x - 4, if two of its zeros are √2 and - √2 .

Answer 1

Answer:

1,2

Step-by-step explanation:

(x-√2)(x+√2)=x^2-2

now

(x4 - 3x3 +6x - 4)/(x2-2)

=x2-3x+2

=(x-1)(x-2)

so the zeros are √2,-√2,1,2