find the altitud at which the acceleration due to gravity is 25% of the surfacs of the earth
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acceleration due to gravity is 25% of the surfacs of the earth= g = g0/4
(g0 is acceleration due to gravity at earth surface)
So from equation
g=g0 [1 - (2h/R)]
1/4 = 1 - (2h/6400)
2h/6400 = 3/4
2h = 4800
So,
h = 2400 km
(g0 is acceleration due to gravity at earth surface)
So from equation
g=g0 [1 - (2h/R)]
1/4 = 1 - (2h/6400)
2h/6400 = 3/4
2h = 4800
So,
h = 2400 km
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