Find the altitude and area of an isosceles traingle whose perimeter is 64 cm and whose base is 24 cm
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Answer
Area of triangle = 1/2×B×H
192=1/2×24×H
H=192×2/24
H=16cm
Now, we know that the altitude of an isoceles triangle bisects the base .
Hence, using pythogoras theoram:
We will get the equal sides as,
Squarerootof(162+122)
= square root of ( 256+144)
=20cm.
Thus , the perimetre will be 20+20+24 = 64cm.
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