Question

find the altitude and area of an isosceles triangle whoes perimeter is 64 cm and whoes base is 24 cm.​

Answer 1

In isosceles triangle two angles are equal

Let it be x

A=? ,base=16cm , Perimeter=24

Perimeter=a+b+c

64 =x+24+x

64=2x+24

64-24=2x

40=2x

x=40÷2

x=20

S=1÷4×perimeter

=1÷4×64

=16cm

Area=✓s(s-a)(s-b)s-c)

=16(16-20)(16-24)16-20)

=-512cm