Question

Find the altitude and area of an isosceles triangle whose perimeter is 64 cm and
whose base is 24 cm.
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Answer 1

Answer:

Step-by-step explanation:

Let equal side be 'a'.

Perimeter = 64 cm = a+a+base

64 = 2a +24

2a = 40

a=20cm

Now, altitude to base of isosceles triangle can be found using pythagoras theorem.

(Altitude)^2 + (Half base)^2 = (Equal side)^2

(Altitude)^2 + (12)^2 = 20 ^ 2

(Altitude)^2 = 400 - 144 = 256

Altitude = √256 = 16 cm

And Area of triangle = 1/2 x (Base) x (Height) = 16 * 24 /2

=8 * 24 = 192 sq cm