Question

find the altitude at which the acceleration due to gravity is 25% of that at the surface of the earth. [gh/g = 25%]​

Answer 1

not sure what the answer is

Answer 2

Answer:

Explanation:

Let the acceleration due to gravity at earth's surface be 100

Therefore: 100=GM/R^2......(1)

We have to find altitude where this acceleration due to gravity becomes 25% (25 in this case)

Therefore: 25=GM/(R1)^2......(2)

Divide equation 1 by equation 2 we get

100/25= GM/(R)^2 x (R1)^2/ GM

4= (R1)^2/(R)^2

taking square root on both sides we get,

2= R1/R

Therefore, R1=2R

It means at a distance 2R from tue centre of earth the acceleration due to gravity will be 25% of its current value