Question

find the altitude if in a triangle area is equal to 132 CM square and base is equal to 11 cm

Answer 1

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Given:
Area = 132 ${cm}^{2}$
Base = 11 cm

Area of triangle=$\frac{1}{2}$×Base×Altitude
$altitude = \frac{area×2}{base} \\ = \frac{132×2}{11} \\ = 24cm$

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