Question

find the altitude of a parallelogram whose base and area are 11.2cm and 168sq.cm,respectively
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Answer 1

Answer:

The Height of the parallelogram is 15 cm.

Step-by-step explanation:

Given :

Base of the parallelogram = 11.2 cm

Height of the parallelogram = 168 cm²

To find :

The Height of the parallelogram

Solution :

$\boxed{\sf{Area=Base \times Height}}$

Let the height be as h

$\sf{\implies} \: 168 = 11.2 \times h \\ \\ \sf{\implies} \: h = \dfrac{168}{11.2} \\ \\ \sf{\implies} \: h = \dfrac{1680}{112} \\ \\ \sf{\implies} \: h = 15$

Height = 15 cm

$\therefore$ The Height of the parallelogram is 15 cm.

Answer 2

Question :-- find the altitude of a parallelogram whose base and area are 11.2cm and 168sq.cm,respectively ?

Formula used :--

→ Area of parallelogram is given by = Base length * Altitude on same base .

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Solution :--

Given :-

→ Area of ll gm = 168cm².

→ Base Side = 11.2cm.

→ Altitude On base = ?

Putting values in above told formula we get,

→ Area = Base * Altitude

→ 168 = 11.2 * Altitude

→ 168 = (112/10) * Altitude .

→ 168 * 10 = 112 * Altitude .

→ 1680 = 112 * Altitude

→ Altitude = (1680/112)

→ Altitude = 15cm .

Hence, Altitude length on Same base is 15cm.

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★★Extra Brainly Knowledge★★

✯✯ Some Properties of a Parallelogram ✯✯

→ Opposite sides are parallel by definition.

→ Opposite sides are congruent.

→ Opposite angles are congruent.

→ Consecutive angles are supplementary.

→ The diagonals bisect each other.

→ Perimeter of Parallelogram = 2(sum of two adjacent side).