Question

find the altitude of a rhombus whose area and perimeter are 98 CM square and 28 CM respectively

Answer 1

hey dude

Here's ur answer...


perimeter of rhombus=28cm

length of the side=28/4

=7cm

area of the rhombus=98cm²

here the side of rhombus be base.

b×h=98cm²

7×h=98cm²

h=98/7

h=14

hence, altitude of rhombus is 14cm.

hope this helps u...


mark me brainlist♥♥♥♥♡♥♥♥

Answer 2

$all \: sides \: of \: a \: rhombus \: are \: congruent \:$

$so \: perimeter = 4 \times side \:$
$28 = 4 \times side$

$\frac{28}{4} = side$

$7 = side$

$side \: = 7cm$

_______________________________

$area = base \times height$

$98 = 7 \times height$

$\frac{98}{7} = height$

$14 = height$

$height = 14cm$
Therefore,
Altitude of the rhombus=14cm
________________________________
Some extra information:

What is perimeter?
The distance around a two-dimensional shape. 
_________________________
What is area?
Area is the amount of two-dimensional space taken up by an object
_________________________
The perimeter of the circle is called circumference.
_________________________

HOPE THIS HELPS YOU!! ^_^
_______________________________