Find the altitude of a rhombus whose area is 320 cm (sq)and side is 5 cm
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ABCD is a rhombus whose base AB = b, DB ⊥ AC DB = d₁ AC = d₂ and the altitude from C on AB is CE, i.e., h.
Area of rhombus ABCD = 2 Area of ∆ ABC
= 2 × 1/2 AB × CD sq units.
= 2 × 1/2 b × h sq. units
= base x height sq. units
Also, area of rhombus = 4 × area of ∆ AOB
= 4 × 1/2 × AO × OB sq. units
= 4 × 1/2 × 1/2 d₂ × 1/2 d₁ sq. units
= 4 × 1/8 d₁ × d₂ square units
= 1/2 × d₁ × d₂; where d₁ and d₂ are diagonals.
Area of rhombus ABCD = 2 Area of ∆ ABC
= 2 × 1/2 AB × CD sq units.
= 2 × 1/2 b × h sq. units
= base x height sq. units
Also, area of rhombus = 4 × area of ∆ AOB
= 4 × 1/2 × AO × OB sq. units
= 4 × 1/2 × 1/2 d₂ × 1/2 d₁ sq. units
= 4 × 1/8 d₁ × d₂ square units
= 1/2 × d₁ × d₂; where d₁ and d₂ are diagonals.
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