Find the altitude of a rhombus whose diagonals are 24 cm and 18cm
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a²=(24/2)² + (18/2)²,
a²=12² + 9²,
a²=144 + 81,
a²=225,
then
a=√225,
a=15 cm,
therefore
Base × height = 1/2 × Ist diagonal × IInd digonal,
then
15 × height =1/2 × 24 × 18,
15 × height =12×18,
then
height =14.4 cm
a²=12² + 9²,
a²=144 + 81,
a²=225,
then
a=√225,
a=15 cm,
therefore
Base × height = 1/2 × Ist diagonal × IInd digonal,
then
15 × height =1/2 × 24 × 18,
15 × height =12×18,
then
height =14.4 cm
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