Question

find the altitude of a Trapezium if the sum of its parallel sides is 17 cm and its area is 340 CMsquare

Answer 1

The height of trapezium is 40cm$area \: of \: trapezium = \frac{1}{2} sum \: of \: parallel \: sides \: \times height \\ 340 = \frac{1}{2} \times 17 \times h \\ = \frac{17h}{2} = 340 \\ 17h = 340 \times 2 \\ = 17h = \: 68 0 \\ h = \frac{680}{17} \\ h = 40$

Answer 2

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Here is your answer
Sum of parallel sides = 17 cm
Area = 340 Sq.cm
Let altitude = x cm

As we know the formula
Area = 1/2(Sum of parallel sides)(altitude)
$340 = \frac{1}{2} \times (17) \times x \\ x = \frac{2 \times 340}{17} \\ x = 40 \: cm$
Therefore
Altitude is 40 cm

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