find the altitude of a Trapezium is the sum of the length of whose base is 6 cm and the area is 5.25 CM square
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Area=1/2×(s1+s2)×h
5.25=1/2×h×6
(2 will cancel 6 and it replaced with 3)
5.25/3= h
H=1.75
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Given,
Sum of the length of the bases = 6 cm
Area = 5.25 cm sq.
To find,
Altitude of Trapezium
Solution,
We know that the formula of the area of trapezium
= 1/2*(sum of parallel sides)*Height
Therefore,
we have,
5.25 = 1/2*(6)*x. (Let the height be x)
x = (2*5.25)/6
x=1.75 cm
So, The altitude of the trapezium = 1.75 cm.
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