Question

Find the altitude of a trapezium, the sum of the length of whose parallel side is 9.5 cm and whose area is 38 cm².
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Answer 1

Step-by-step explanation:

GIVEN

Sum of parallel sides = 9.5 cm

Area = 38 Sq. cm

Altitude( height) = ?

$area \: of \: \: trapezium = 38 \\ \frac{1}{2} (sum \: \: of \: \: prallel \: \: side) \times (height) = 38 \\ \\ \frac{1}{2} (9.5) \times (height) = 38 \\ \\ height = \frac{38 \times 2}{9.5} \\ \\ height \: = 8 \: \: cm$

So altitude of trapezium is 8 cm

Answer 2

Step-by-step explanation:

GIVEN

Sum of parallel sides = 9.5 cm

Area = 38 Sq. cm

Altitude( height) = ?

\begin{gathered}area \: of \: \: trapezium = 38 \\ \frac{1}{2} (sum \: \: of \: \: prallel \: \: side) \times (height) = 38 \\ \\ \frac{1}{2} (9.5) \times (height) = 38 \\ \\ height = \frac{38 \times 2}{9.5} \\ \\ height \: = 8 \: \: cm\end{gathered}

areaoftrapezium=38

2

1

(sumofprallelside)×(height)=38

2

1

(9.5)×(height)=38

height=

9.5

38×2

height=8cm

So altitude of trapezium is 8 cm

I hope it will help you