Question

Find the altitude of a

trapezium, the sum of the

lengths of whose bases is3.25

cm and whose area is 26 Sq.cm​

Answer 1

Answer:

16

Step-by-step explanation:

area of trapezium = (1/2)* (b1+b2)*h

26 = (1/2) * (b1+b2) * 3.25

26*(2/1) / 3.25=(b1+b2)

=16

Answer 2

✬ Altitude = 16 cm ✬

Step-by-step explanation:

Given:

• Sum of the lengths of bases of trapezium is 3.25 cm.
• Area of trapezium is 26 cm².

To Find:

• What is the meaure of altitude of trapezium ?

Solution: Let a and b be the two sides or bases of trapezium. Therefore,

➯ Sum of bases = a + b

➯ a + b = 3.25 cm

As we know that

★ Ar. of Trapezium = 1/2(sum of || sides)(distance between them) ★

A/q

• Area is 26 cm²

$\implies{\rm }$ 26 = 1/2(a + b)h

$\implies{\rm }$ 26 = 1/2(3.25)h

$\implies{\rm }$ 26 = 3.25/2 $\times$ h

$\implies{\rm }$ 26 $\times$ 2 = 3.25h

$\implies{\rm }$ 52/3.25 = h

$\implies{\rm }$ 16 = h

Hence, altitude of trapezium is 16 cm.