Question

Find the altitude of a trapezium, the sum of the lengths of whose bases is 6.5cm and whose area is 26 cm². with explanation

Answer 1

Area of trapezium = 1/2(a+b)h

26= 6.5/2×h

26×2/6.5 =h

h= 8 cm

Answer 2

Answer:8cm

Step-by-step explanation:

area of trapezium=26cm2

let altitude be= x

p & q are parallel sides of a trapezium

p+q = 6.5 cm

--> 1/2 x (a+b) x 26

--> 26x2/66

--> 52/6.5

--> = 8cm

altitude is 8 cm

thank you