Question

find the altitude of a Trapezium whose area is 0.88 m square and the sum of its parallel side is 2.2​

Answer 1

Height of the given trapezium is 0.8 m

1) The area of a Trapezium is given by the formula :

A  = (a+b)*h/2

where a and b are the opposite parallel sides or the bases of the trapezium and h is the height or altitude of the trapezium

2) Here, the given altitude h is 0.88 square m and the sum of parallel sides a+ b is 2.2 m

3) Substituting the values in the formula :

0.88 = 2.2*h/2

h = 0.88/1.1

h = 0.8 m

Answer 2

Step-by-step explanation:

area of trap.=1/2×h×(s1+s2)

o.88=1/2×h×2.2

h=0.88/1.1

h=0.8 cm

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