Question

Find the altitude of a trapezium whose area is 105 cm² and whose bases are 14 cm and 7 cm.

Please thanks ak2127863 ID this ID is in my following​

Answer 1

Step-by-step explanation:

Area of Trapezium => 105cm^2

1/2 x sum of parallel side x h = 105

1/2 x 14 + 7 x h = 105

1/2 x 21 x h = 105

h = 105 x 2 / 21

h = 10cm

Answer 2

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

Given thαt,

• The αreα of α trαpezium is 105 cm².
• The bαses αre 14cm αnd 7cm.

◾️We need to find the αltitude of α trαpezium.

_____________

$\large\star{\boxed{\sf{\orange{Area_{(trapezium)}=\dfrac{1}{2}\times(height)\times(Sum\:of\:parallel\:sides)}}}}$

Let's αssume thαt αltitude or height be a.

• Substitute the vαlues.

$\longrightarrow{\sf{105cm^{2}=\dfrac{1}{2}\times a \times (14cm+7cm)}}$

$\longrightarrow{\sf{105cm^{2}=\dfrac{a}{2}\times(21)}}$

$\longrightarrow{\sf{105cm^{2}=\dfrac{21a}{2}}}$

$\longrightarrow{\sf{105cm^{2}\times 2=21a}}$

$\longrightarrow{\sf{210cm^{2}=21a}}$

$\longrightarrow{\sf{a=\dfrac{210}{21}}}$

$\large{:}\implies{\boxed{\bf{\orange{a=10cm}}}}$

Hence, the height or αltitude of the trαpezium is 10cm.

And we αre done! :D

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