Question

find the altitude of a trapizium, the sum of length of whose base is 6.5cm and whose area is 26cm^2​

Answer 1

Given:

• Base :- 6.5 cm
• Area of parallelogram :- 26 cm²

To Find:

• Altitude of trapezium

Solution:

⠀⠀⠀⠀⠀⠀⠀⠀★ A = 1/2 × (a + b) × h

Where,

• A = area
• (a + b) = sum of parallel sides
• h = altitude or height

Putting the values:

→ 26 = 1/2 × (6.5) × h

→ 52 = 13/2 × h

→ h = 52 × 2/13

→ h = 8 cm

Hence,

• Altitude of trapezium = 8 cm.

Answer 2

$\large{\boxed{\tt{Answer}}}$

$\:\:\:\normalsize\sf{Altitude\:of\: the\: trapezoid= \bold{8\:cm}}$

$\:$

$\large{\boxed{\tt{Explanation}}}$

$\large\underline{\bf{Given:}}$

$\:\:\:\:\:\normalsize{\sf{Sum\:of\:parallel\:sides\:of\:a\:trapezoid=6.5\:cm}}$

$\:\:\:\:\:\normalsize{\sf{Area\:of\:the\:trapezoid=26\:{cm}^{2}}}$

$\large\underline{\bf{To\:find:}}$

$\:\:\:\:\:\normalsize{\sf{The\:altitude\:of\:the\: trapezoid.}}$

$\large\underline{\bf{Solution:}}$

$\small\underline{\boxed{\sf{{Area}_{(Trapezoid)}= \frac{1}{2} \times (Sum \: of \: parallel \: sides) \times Height\:sq.units}}}$

$\:\:\:\:\:\large\implies{\sf{26=\frac{1}{2} \times 6.5 \times \red{h}}}$

$\:\:\:\:\:\large\implies{\sf{26=3.25 \times \red{h}}}$

$\:\:\:\:\:\large\implies{\sf{\red{h} = \frac{26}{3.25}}}$

$\:\:\:\:\:\large\implies{\sf{\red{h=8\:cm}}}$

$\:\:\:\:$

$\normalsize{\sf{Hence,\:the\: altitude\:of\:the\: trapezoid\:is\: {\underline{\pink{8\:cm}}.}}}$

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