find the altitude of a trapizium, the sum of length of whose base is 6.5cm and whose area is 26cm^2
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4
Answer:
Let us consider the altitude of a trapezium as h
so the sum of lengths of parallel sides are 6.5cm
area=26cm²
we know area of trapezium=1/2 h(a+b)
1/2 h(6.5) =26
h(6.5) =26*2/1
h(6.5) =52
h=52/6.5
h=8cm
so altitude of a trapezium is 8cm
Answered by
9
area of trapezium =1/2h(a+b)
1/2×h(6.5)=26
or,h=26×2/6.5
or,h=8
height or altitude =8cm
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