Question

find the altitude of a trapizium, the sum of length of whose base is 6.5cm and whose area is 26cm^2​

Answer 1

Answer:

8 cm

Step-by-step explanation:

area of trapezium = $\frac{(a+b)h}{2}$

area = 26 cm²

sum of sides = 6.5 cm

26 = $\frac{6.5*h}{2}$

52 = 6.5h

h = 52/6.5 = 8 cm

therefore height between the parallels is 8  

Answer 2

Given :

⬤ Sum of Length of Base of Trapezium is 6.5 cm .

⬤ Area of Trapezium is 26 cm² .

To Find :

⬤ Altitude of Trapezium .

Formula Used :

$\bf[\:{Area \: of \: Trapezium = \dfrac{1}{2}\times{(Sum\:of\: Parallel\:Sides)}\times{Height}}\:]$

Solution :

• Sum of Length of Base is = 6.5 .
• Area of Trapezium = 26 cm².

According to the Formula :-

26 = 1/2 × 6.5 × h

(26 × 2) = 6.5 × h

52 = 6.5h

52/6.5 = h

8 = h

Therefore , The Altitude of Trapezium is 8 cm .