Question

find the altitude of a triangle if its area is 25 are and base is 20 metre answer is 250 metre​

Answer 1

Answer:

Area of triangle = 25 ares

We know that 1 are = 100 sq m

So, 25 ares = 25*100

= 2500 sq m

So, the area of the given triangle is 2500 sq m

Base = 20 m

Area of triangle = 1/2*Base*Height

⇒ 2500 = 1/2*20*H

⇒ 2500 = 10H

⇒ H = 2500/10

⇒ H = 250

So, the height or altitude of the given triangle is 250 m

Step-by-step explanation:

hope it is useful

Answer 2

$\bf{\underline{\underline{Correct\:Question:-}}}$

find the altitude of a triangle if its area is 25 ares and base is 20 metre.

$\bf{\underline{\underline{Given:-}}}$

• Area of ∆ is 25 Ares

→ 1 Ares = 100 m

• Area of ∆ is 25 × 100 m
• Area of ∆ is 2500 m
• Base of ∆ is 20m

$\bf{\underline{\underline{To\:Find:-}}}$

• Altitude of ∆ or height ?

$\bf{\underline{\underline{Formula:-}}}$

$\sf{\boxed{\mathscr{Area\:of\: Triangle = \frac{1}{2}×Base×height}}}$

$\bf{\underline{\underline{Solution:-}}}$

$\sf → 2500= \dfrac{1}{2}×20×h$

$\sf → 2500=1×10×h$

$\sf → 2500 = 10h$

$\sf → h = \dfrac{2500}{10}$

$\sf → h = 250m$

$\bf{\underline{\underline{Hence:-}}}$

• The required height of ∆ is 250m

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