Question

Find the altitude of a triangle whose area is 58.5 cm and corresponding base is 13cm.​

Answer 1

Step-by-step explanation:

area of ∆= 1/2× base × height

58.5= 1/2×13× height

58.5×2/13= height

height= 9

Answer 2

Answer:

9cm

Step-by-step explanation:

Area of Δ= 58.5 cm

Base of Δ= 13 cm

Height/Altitude= ??

We know that area = 1/2 base×height

$\frac{1}{2} X 13X h= 52.5\\13Xh= 52.5X2\\13Xh= 117\\h= \frac{117}{13}\\h= 9 cm$

So Altitude of Δ= 9cm

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