Question

Find the altitude of a triangle whose area is 784 sq.cm and base is 32 cm

Answer 1

Area = 1/2 × b × h

784 = 1/2 × 32 × h

h = 49 cm ......

Answer 2

Given:

• Area of the triangle = 784 sq. m.
• Base of the triangle = 32 cm.

To Find:

Altitude of the triangle.

Solution:

Given area = 784 Sq.cm, Base = 32 cm, Altitude = ?

$H = \frac{2 \times Area}{B}$

$H = \frac{2 \times 784}{32} =49cm.$

$:\implies \boxed{Altitude \: of \:the \: triangle = 49cm.}$