Question

FinD the altitude of a triangle whose base and area are 16.4 and 246cm2

Answer 1

given,
Base of triangle = 16.4 cm
Area = 246 sq.cm
Altitude = area / base
=> 246/16.4
=> 15 cm
Altitude = 15 cm

Answer 2

Answer:

Altitude (h) = 30cm

Explanation:

Dimensions of a triangle:

Base (b) = 16.4 cm

Let altitude = h cm

Area (A) = 246cm²[ given ]

=> (bh)/2 = 246 cm²

=> (16.4 cm × h)/2 = 246cm²

=> h = (246 × 2 )/16.4

=> h = 30 cm

Therefore,

Altitude of the triangle (h)=30cm

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