Question

find the altitude of a triangle whose base and area are 16.4cm and246cm
square

Answer 1

Answer:

30 cm

Step-by-step explanation:

We know that

area of triangle = 1/2(base)(corresponding altitude)

∴ 1/2 (16.4) (Altitude) = 246

Altitude = (246×2)/16.4

Altitude = 30 cm

∴ Altitude of the triangle corresponding to base 16.4 cm is 30 cm

Answer 2

Given :

A triangle whose base and area are 16.4 cm and 246 sq.cm.

To Find :

Find the altitude

Solution:

Let the altitude of triangle be x

Base of triangle = 16.4 cm

Area of triangle =$\frac{1}{2} \times base \times Height$

Area of triangle =$\frac{1}{2} \times 16.4 \times x$

We are given that area of triangle is 246 sq.cm.

So, $\frac{1}{2} \times 16.4 \times x = 246\\x =\frac{246 \times 2}{16.4}\\x=30$

Hence The altitude of triangle is 30 cm