Question

Find the altitude of a triangle whose base is 12 cm, and area is 672 square cm?

Answer 1

Answer:

• Altitude of triangle is 112 cm

Step-by-step explanation:

Given

• Base of triangle = 12 cm
• Area of triangle = 672 cm²

To find

• Altitude or height of triangle

Solution

Area of triangle = 1/2 × base × height

• 672 = 1/2 × 12 × height
• 672 = 12/2 × height
• 672 = 6 × height
• height = 672/6
• height = 112

Hence, the height or altitude of triangle is 112 cm

Verification

• Area = 1/2 × base × height
• 672 = 1/2 × 12 × 112
• 672 = 6 × 112
• 672 = 672
• L.H.S = R.H.S

Learn more

• Area of square = side × side
• Area of rectangle = length × breadth
• Area of circle = π × radius × radius
• Area of parallelogram = base × height

Answer 2

Given:

A triangle with

• Base = 12 cm
• Area = 672 cm²

What To Find:

We have to find the altitude of the triangle.

How To Find:

To find the altitude, we will use the formula i.e.,

• $\rm Area \: Of \: Triangle = \dfrac{1}{2} \times Base \: \times Height \: (Altitude)$

Solution:

Using the formula,

$\rm \Rightarrow Area \: Of \: Triangle = \dfrac{1}{2} \times Base \: \times Height \: (Altitude)$

Substitute the values,

$\rm \Rightarrow 672 \: cm^2 = \dfrac{1}{2} \times 12 \: cm \: \times Height \: (Altitude)$

Cancel 2 and 12,

$\rm \Rightarrow 672 \: cm^2 = 6 \: cm \: \times Height \: (Altitude)$

Take 6 to LHS,

$\rm \Rightarrow \dfrac{672}{6} = Height \: (Altitude)$

Divide 672 by 6,

$\rm \Rightarrow 112 \: cm = Height \: (Altitude)$

$\overline {\boxed {\rm \therefore The \: altitude \: of \: the \: triangle \: is \: 112 \: cm.}}$