Question

Find the altitude of a triangle whose base is 12cm and area is 336cmsquare

Answer 1

$\huge\mathcal{Heya}$

$\mathsf\red{Given \ :-}$

Base of a triangle = 12 cm

Area of a triangle = 336 cm²

$\mathsf\red{To \ find \ :-}$

Altitude / Height of a triangle = ?

$\mathsf\red{Solution \ :-}$

Let the altitude of a triangle = x cm

By using formula of Area of a triangle,

Area of a triangle = 1 / 2 × Base × Altitude

Area of a triangle = 1 / 2 × BC × AB

Putting the known values, we get

336 = 1 / 2 × 12 × x

336 = 6 × x

x = 56

Hence,

$\tt\green{Altitude \ = \ 56 \ cm}$

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Answer:

Hence, height / Altitude of triangle will be 56 cm

Step-by-step explanation:

In context to question asked,

We have to determine the altitude / Height of triangle.

As per data given in the question,

We have,

Area of triangle = 336 Sq. cm

Base of triangle = 12 cm

As we know that,

Triangle is a three sided figure,

Sum of all angles of the triangle is 180 degree.

The area of triangle can be determined by using formula $Area = \frac{1}{2} \times base \times Height$

So, for determining the height of triangle we will put the value of base and area given in the question in above formula,

Thus we will get it as,

$Area =\frac{1}{2} \times 12 \times h\\=>336 = \frac{1}{2}\times 12 \times h\\=>h = \frac{336 \times 2}{12}\\=>h = 28\times 2 = 56\:cm$