Question

find the altitude of parallelogram whose area is 1423 .5 cm and base is 19 . 5 cm​

Answer 1

Answer:

That's your answer

Step-by-step explanation:

Area of a parallelogram=base×height.

⇒54=15×height

⇒ height=

15

54

=

5

18

=3.6cm

∴ height of the parallelogram=3.6cm

Answer 2

Given:-

• Area of the parallelogram is 1423.5 cm².
• Base of the parallelogram is 19.5 cm.

⠀

To find:-

• Altitude of the parallelogram.

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Solution:-

Here,

• Base (b) = 19.5 cm
• Area of the parallelogram = 1423.5 cm².

⠀

☆Area of parallelogram = base × height

→ 1423.5 = 19.5 × h

→ h = 1423.5/19.5

→ h = 73 cm

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Hence,

• the altitude of the parallelogram is 73 cm.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\; Square\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$