find the altitude of rhombus whose area is 315 CM square and one diagonal is 30 cm
Answers
Answer:
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Step-by-step explanation:
Suppose length of a side in the rhombus ABCD is a (AB=BC=CD=DA=a), then 4a=180 or a= 45 and the area is given by 0.5a^2sinABC=315 or sinABC=630/2025=14/45
The altitude = BC.sinABC=45.(14/45)=14
Hence answer is 14
Answer:
10.5 cm.
Step-by-step explanation:
We know that the diagonals of a rhombus are perpendicular to each other. therefore if one of then is given then the other diagonal is the altitude.
and also we know that the area of a rhombus = product of diagonals.
________
Given: Diagonal A = 30. Area of Rhombus = 315Cm².
to find: the altitude of the rhombus (basically the length of the other diagonal.
_______________
Let the other diagonal be 'x'.
______________________
315Cm²=30Cm × X CM.
X CM= 315/30 = 10.5 Cm.