Question

Find the altitude of right angled triangle whose hypotenuse is 15 cm and base is 9 cm..

Answer 1

✬ Altitude = 12 cm ✬

Step-by-step explanation:

Given:

• Meaure of hypotenuse is 15 cm.
• Meaure of base is 9 cm.

To Find:

• What is meaure of altitude of triangle ?

Solution: Let ABC be a right angled triangle at B in which

• AB = Perpendicular or altitude
• BC = Base {9 cm}
• AC = Hypotenuse {15 cm}

Using Pythagoras Theorem, as we know that

★ H² = P² + B² ★

$\implies{\rm }$ AC² = AB² + BC²

$\implies{\rm }$ 15² = AB² + 9²

$\implies{\rm }$ 225 = AB² + 81

$\implies{\rm }$ 225 – 81 = AB²

$\implies{\rm }$ 144 = AB²

$\implies{\rm }$ √144 = AB

$\implies{\rm }$ 12 = AB

Hence, the meaure of altitude of triangle is 12 cm.

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• Verification •

=> 225 = AB² + 81

=> 225 = 12² + 81

=> 225 = 144 + 81

=> 225 = 225

$\large\boxed{\texttt{Verified}}$

Answer 2

Step-by-step explanation:

____________________

Question :-

• Find the altitude of right angled triangle whose hypotenuse is 15 cm and base is 9 cm..

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Given :-

• hypotenuse = 15 cm
• base = 9 cm

____________________

To Find :-

• the altitude of right angled triangle .

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Solution :-

Hypotenuse² = base² + height²

15² = 9² + x²

x² = 225 - 81

x² = 144

x = √144

x = 12

height = 12 cm

The area of a right angled triangle is

= ½ × base × height

= ½ × 9 × 12

= 54 cm²

Hence The area of a right angled triangle is 54 cm²

Internal Information :-

• rectangle= length × breadth
• square= side × side
• triangle= ½ × base × height