Question

find the altitude of the trapezium whose sum of the parallel sides is 6.5cm and area is 26cm²​

Answer 1

Answer:

altitude = 8 cm

Step-by-step explanation:

We know, Area of a trapezium is h(a+b)/2 where h is altitude; a and b are parralel sides.

So, h(6.5)/2=26cm^2

   =h(3.25)=26

    =h=26/3.25

     =h=8cm

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Pls mark me the brainlisest.

Answer 2

Altitude of the trapezium is 8 cm

Given

sum of the parallel sides is 6.5 cm

Area of the parallelogram is 26 cm²

To Find

Altitude of the trapezium

Knowledge required

$\bf \pink{\bigstar\ \; A=\dfrac{1}{2}\times (a+b)\times h}$

where ,

• A denotes Area
• ( a + b ) denotes sum of parallel sides
• h denotes altitude / height

Solution

Given ,

• ( a + b ) = 6.5 cm
• A = 26 cm²
• h = ? cm

Apply formula ,

$\bf \red{A=\dfrac{1}{2}\times (a+b)\times h\ \bigstar}\\\\\rm \to 26=\dfrac{1}{2}\times (6.5)\times h\\\\\to \rm 52=\dfrac{13}{2}\times h\\\\\to \rm h=\dfrac{52\times 2}{13}\\\\\to \bf \green{h=8\ cm\ \bigstar}$

So , Altitude of the trapezium = 8 cm