find the altitude of the triangle whose area equal 104 cm2 base = 13
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hey the answer is. ..
hope it helps uu frnd
GM ☺☺
hope it helps uu frnd
GM ☺☺
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tr467:
thanks
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we know that area of triangle
let altitude=h
![\frac{1}{2} \times \: hight \times base \frac{1}{2} \times \: hight \times base](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+%5C%3A+hight+%5Ctimes+base)
1/2×13×h=104
13/2×h=104
h=104×2/13
h=8×2
h=16
let altitude=h
1/2×13×h=104
13/2×h=104
h=104×2/13
h=8×2
h=16
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