Question

find the altitude of trapezium the sum of lengths of whose bases is 7.5 cm and whose area is 67.5 CM​

Answer 1

Step-by-step explanation:

area of trapezium = 1/2 × h × (a + b)

h = height a, b are the parallel side

$67.5 = \frac{1}{2} \times h \times (7.5) \\ h = \frac{67.5 \times 2}{7.5} \\ h = \frac{135}{7.5} \\ h = 18cm$

the altitude of trapezium is 18 cm

hope you get your answer

Answer 2

Answer:

its ans is h-8cm .

mark me brainlisted