Question

find the altitude of trapezium whose area is 105cm square and bases are 14cm and 7cm ????
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Answer 1

Answer:

Solution :-

Area of trapezium = 105 cm²

Bases of trapezium = 14cm and 7cm

Step-by-step explanation:

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Answer 2

Given :-

• A trapezium whose area is 105cm square and bases are 14cm and 7cm.

To find :-

• Altitude of trapezium

Solution :-

• Area of trapezium = 105 cm²

• Bases of trapezium = 14cm and 7cm

As we know that

→ Area of trapezium = ½ (a + b) × h

Where " (a + b) " is sum of parallel sides and " h " is Altitude.

• According to the question

→ Bases of trapezium = parallel sides

→ Area of trapezium = 105 cm²

→ ½ (a + b) × h = 105

→ ½ (14 + 7) × h = 105

→ ½ × 21 × h = 105

→ 21/2 × h = 105

→ h = 105 × 2/21

→ h = 10 cm

Therefore,

• Height of trapezium is 10cm

More to know :-

• Area of circle = πr²

• Circumference of circle = 2πr

• Perimeter of reactangle = 2(l + b)

• Perimeter of square = 4 × side

• Area of square = side × side

• Area of rhombus = ½ × product of diagonals

• Area of parallelogram = base × height