Math, asked by shubham1331, 1 year ago

Find the AM OF 2,4,6,8....2N

Answers

Answered by TheLifeRacer
9
Heya

AM=1/2(a+l)
let a=2
and l=2n .

now AM=1/2(2+2N)

AM=1+N

hope it help you .

@rajukumar ☺
Answered by aishwaryahk
0

Answer:

The Arithmetic mean of given series is (n + 1)

Step-by-step explanation:

The given series is 2, 4, 6, 8......,2n

Let the number of terms in the series be n

The series can be written as

2 (1, 2, 3, 4,......,n)

We know that sum of first n natural numbers is given by

Sn=\frac{n(n+1)}{2}

Therefore the sum of n terms of given series is given by

S_{2n} = 2(\frac{n(n+1)}{2} )

    = n(n + 1)

AM= \frac{sum}{n}

Sum = sum of terms in the series

n = number of terms in the series

AM =\frac{n(n+1)}{n}

AM = n + 1

Where n is the number of terms in the given series

Therefore the Arithmetic mean of the given series 2, 4, 6, 8......,2n is

(n + 1)

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