find the ammeter reading in the circuit
shown in the fig
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Explanation:
- moving towards Q there is a resistance of 6ohms which in series with whole circuit joining Q forward
- From Q current is divide into two wires which means resistance on both wires are in parallel
- Q is furthur divide into two wires again there is a small parallel combination
Now 5 ohm and 7ohm are in series hence there resistance is 5+7=12ohm
Now 6ohm and 12ohm resistance are in parallel hence there effective resistance is 4ohm
Now 4ohm and 8ohm resistance are in parallel hence there effective resistance is 8/3 ohm
Now 1 ohm and 8/3 ohm resistance are in series there effective resistance is 11/3ohm
Hence effective resistance of circuit is 11/3ohm
voltage is 11V
Than current is V/R
Hence current =3A
Reading of Ammeter=3
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