Question

find the ammount on compound interest a sum of ₹5000 for 2years at the rate of 2% per annum​

Answer 1

$\Large\sf{{{AnsWer:}}}\\ \\ \tt Compound \:Interest = Rupees \:202 \\ \\ \large \sf Given:\\ \\ \tt Principle = Rupees \:5000\\ \\ \tt Time = 2\:Years \\ \\ \tt Rate = 2 \%\\ \\ \tt Compound \:Interest =?$

$\Large \sf{{{Step\: by\: step \:explanation:}}}$

$\implies \tt A = P \left(1+\dfrac{r}{100}\right)^n \\ \\ \tt Substituting\: the\: values, \:we \:get, \\ \\ \implies \tt 5000 \left(1+\dfrac{2}{100}\right)^2 \\ \\ \implies \tt 5000 \left( \dfrac{102}{100}\right)^2 \\ \\ \implies \tt 5000 \times \dfrac{102}{100}\times \dfrac{102}{100} \\ \\ \implies \tt 51 \times 102 \\ \\ \implies \tt 502 \\ \\ \tt Compound \:Interest = Amount - Principle \\ \\ \implies \tt 5202 - 5000 \\ \\ \implies \tt {\green {\boxed{202}}}$

Answer 2

$\huge\bold\green{Question}$

Find the ammount on compound interest a sum of ₹5000 for 2 years at the rate of 2% per annum ?

$\huge\bold\green{Answer}$

According to the question we have given :-

•°• Time = 2 Years

•°• Principle = Rs.5000

•°• Rate = 2 %

So, we have to find Compound Interest = ?

$\begin{lgathered}\sf A = P \left(1+\dfrac{r}{100}\right)^n \\ \\ \sf Now \: by \: Substituting\: known\: the\: values, \:we \:get \\ \\ = \sf 5000 \left(1+\dfrac{2}{100}\right)^2 \\ \\ \sf = 5000 \left( \dfrac{102}{100}\right)^2 \\ \\ = \sf 5000 \times \dfrac{102}{100}\times \dfrac{102}{100} \\ \\ = \sf 51 \times 102 \\ \\ = \sf 502 \\ \\ \sf Compound \:Int. = Amount - Principle \\ \\ = \sf 5202 - 5000 \\ \\ \huge \tt {=202}\end{lgathered}$

Hence the compound interest is ₹ 202