Question

find the amount after 2 years if rupees 25000 is invested at a rate of 6 perecentage compounded annualy? ​

Answer 1

Answer:

Interest for the first year =

100

25000×1×20

=5000

Amount after first year = 25000+5000=30000

Interest for second year =

100

30000×1×20

=6000

Amount after second year = 30000+6000=36000

Interest for third year =

100

36000×1×20

=7200(approx)

Answer 2

Answer -

• The amount = Rs 28090.

To find -

• The amount after 2 years if Rs 25000 is invested at a rate of 6% compounded annually.

Step-by-step explanation -

$\mathfrak{\mapsto Amount = 25000 \left(1 + \dfrac{6}{100} \right)^2}$

$\mathfrak{\mapsto Amount = 25000 \left(\dfrac{1 \times 100 + 6 \times 1}{100} \right)^2}$

$\mathfrak{\mapsto Amount = 25000 \left(\dfrac{100 + 6}{100}\right)^2}$

$\mathfrak{\mapsto Amount = 25000 \left(\dfrac{106}{100} \right)^2}$

$\mathfrak{\mapsto Amount = 25000 \times \dfrac{106}{100} \times \dfrac{106}{100}}$

$\mathfrak{\mapsto Amount = 25000 \times \dfrac{11236}{10000}}$

$\mathfrak{\mapsto Amount = \cancel{\dfrac{280900000}{10000}}}$

$\mathfrak{\mapsto Amount = Rs \: 28090}$

Hence -

• The amount after 2 years will be Rs 28090.

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