Question

Find the amount & compound interest on rupees 10000 in 2 years if the rate of interest for the successive years are 20 percent and 10 percent respectively ​

Answer 1

Answer:

Principal (P) = ₹ 10,000

Time (t) = 2 Years

Rate = (R1) = 10%

Rate = (R2) = 20%

Amount = P (1 + (R1/100)) (1 + (R2/100))

= ₹ 10,000 × (1 + (10/100)) (1 + (1 + (20/100))

= ₹10,000 × 11/10 × 6/5 = ₹4545

C.I. = Amount – Principal

= ₹ 15,180 - ₹10,000 = ₹5455

Answer 2

Given,

• P = ₹ 10,000
• T = 2 years
• R(1) = 10%
• R(2) = 20%

Solution,

$amount = p(1 + \frac{r1}{100} ) (1 + \frac{r2}{100} )$

$= 10000(1 + \frac{10}{100} )(1 + \frac{20}{100} )$

$= 10000 \times \frac{11}{10} \times \frac{6}{5}$

$= 2200 \times 6 = 13200$

$compound \: interest = amount - pricipal$

$= 13200 - 10000 = 3200$