Question

Find the amount and compound interest compounded annually on
Rs. 20,000 at 9% p.a. for 2 years
Rs. 10,000 at 6.5% p.a. for 2 years
Rs. 30,000 at 20% p.a. for 23/5 years

Answer 1

Answer:

A=p(1+r/100) ^n

20000(1+9/100) ^2

20000(109/100) ²

20000(11881/10000)

2*11881

amount= 23762 rupees

CI=A-P

CI=23762-20000

ci= 3762rupees

Step-by-step explanation:

Other two will be follow in this process only .

Answer 2

Answer:

Step-by-step explanation:

Question 01:

Find the Amount and Compound interest on ₹ 20,000 at 9% p.a. for 2 years

Answer:

Principle = 20,000

Rate of interest = 9%

Time = 2 yrs

Amt = P( 1 + r/100)ⁿ

Amt = 20,000( 1 + 0.09)²

Amt = 20,000 (1.1881)

Amt = 23,762

CI = Amt - Principle

CI = 23,762 - 20,000

CI = 3,762

Question 02

Find the Amount and Compound interest on ₹ 10,000 at 6.5% p.a. for 2 years

Answer:

Principle = 10,000

Rate of interest = 6.5%

Time = 2 yrs

Amt = P( 1 + r/100)ⁿ

Amt = 10,000( 1 + 0.065)²

Amt = 10,000(1.065)²

Amt = 10,000 (1.134225)

Amt = 11,342.25

CI = Amt - Principle

CI = 11,342.25 - 10,000

CI = 1,342.25

Question 03:

Find the Amount and Compound interest on ₹ 30,000 at 20% p.a. for 23/5 years

Answer:

Principle = 30,000

Rate of interest = 20%

Time = 23/5 yrs i.e. 4.6 i.e. 4 yrs and 6 months

Amt = P( 1 + r/100)ⁿ

Amt = 30,000( 1 + 0.20)⁹/₂

Amt = 30,000(1.20)⁹/₂

Amt = 30,000 (2.2715149)

Amt = 68,145.45

CI = Amt - Principle

CI = 68,145.45 - 30,000

CI = 38,145.45