Math, asked by sanjana38701, 10 months ago

Find the amount and compound interest if principal = ₹500, rate = 5%, n= 3 Years ​

Answers

Answered by fightingstar2005
0

Answer:

Answer:Amount =578.81

Answer:Amount =578.81C. I of 1 year =25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 year

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =525

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 year

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.25

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.253 year

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.253 yearCI = (551.25*5*1)/100

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.253 yearCI = (551.25*5*1)/100=27.56

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.253 yearCI = (551.25*5*1)/100=27.56Amount=551.25 + 27.56

Answer:Amount =578.81C. I of 1 year =25CI+AMOUNT=525C. I of 2 year =26.25C. I +AMOUNT = 551.25C.I of 3 year =27.56CI + AMOUNT =578.81Step-by-step explanation:1 yearCI = (500*5*1)/100=25Amount =500+25 =5252 yearCI = (525*5*1)/100=26.25Amount=525+26.25 =551.253 yearCI = (551.25*5*1)/100=27.56Amount=551.25 + 27.56 =578.81

Answered by sushiladevi4418
0

Amount  = Rs 578.81,  Interest  = Rs 78.81

Step-by-step explanation:

P = 500 , r = 5% , t = 3 Years

Let , the interest is compounded annually.

So, n =1

Now, Amount  =  P\times (1 + \frac{r}{n}) ^{nt}

Here, r = 5%  = 0.05

Now, A = 500 \times (1 + 0.05) ^{3}   = 500 \times (1.05)^{3}   = 578.81

Hence, the compounded Amount is Rs. 578.81

So, Interest =  Amount -  Principal  =  Rs 578.81 - Rs 500

I = Rs 78.81

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