Find the amount and compound interest on
1: Rs 12000 in 2years at 8% per anumm
2:Rs 20,000 in 2years at 10% per annum
Answers
i) Principal = 12000
Time = 2 years
Rate of interest = 8% p.a.
Formula :
Putting up the values :
Compound Interest : Amount - Principal
=> 13996 (-) 12000
=> 1996
_________________
ii) Principal = 20000
Time = 2 years
Rate of interest = 10% p.a.
Formula :
Putting up the values :
Compound Interest = Amount (-) Principal
=> 24200 - 20000
=> 4200
Steps followed :
- Firstly we have noted down the formula of Compound Interest.
- Then taking up the values of Principal and Time and Rate of Interest in the correct places ; we have further solved it.
- Finally when we got the amount ; to find the compound Interest ; we had to subtract Amount from principal amount.
Simple Interest :
Step-by-step explanation:
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Glorious31
Glorious31Brainly Stars
i) Principal = 12000
Time = 2 years
Rate of interest = 8% p.a.
Formula :
\tt{Amount \implies Principal \times{( 1 + \dfrac{R}{100})}^{time}}
Putting up the values :
\tt{ Amount \implies 12000 \times {(1 + \dfrac{8}{100})}^{2}}
\tt{Amount \implies 12000 \times {(\dfrac{108}{100})}^{2}}
\tt{Amount \implies 12000 \times {(\dfrac{27}{25})}^{2}}
\tt{Amount \implies 12000 \times \dfrac{27}{25} \times \dfrac{27}{25}}
\tt{Amount \implies \cancel{12000} \times \dfrac{27}{25} \times \dfrac{27}{\cancel{25}}}
\tt{Amount \implies 480 \times \dfrac{27}{25} \times 27}
\tt{Amount \implies 19.2 \times 27 \times 27}
\tt{Amount \implies 13996.8}
Compound Interest : Amount - Principal
=> 13996 (-) 12000
=> 1996
_________________
ii) Principal = 20000
Time = 2 years
Rate of interest = 10% p.a.
Formula :
\tt{Amount \implies Principal \times{( 1 + \dfrac{R}{100})}^{time}}
Putting up the values :
\tt{Amount \implies Principal \times {(1 + \dfrac{R}{100})}^{time}}
\tt{Amount \implies 20000 \times {(1 + \dfrac{10}{100})}^{2}}
\tt{Amount \implies 20000 \times {(\dfrac{110}{100})}^{2}}
\tt{Amount \implies 20000 \times {(\dfrac{11}{10})}^{2}}
\tt{Amount \implies 20000 \times \dfrac{11}{10} \times \dfrac{11}{10}}
\tt{Amount \implies \cancel{20000} \times \dfrac{11}{10} \times \dfrac{11}{\cancel{10}} }
\tt{Amount \implies \cancel{2000} \times \dfrac{11}{\cancel{10}} \times 11}
\tt{Amount \implies 200 \times 11 \times 11}
\tt{Amount \implies 200 \times 121}
\tt{Amount \implies 24200}
Compound Interest = Amount (-) Principal
=> 24200 - 20000
=> 4200
Steps followed :
Firstly we have noted down the formula of Compound Interest.
Then taking up the values of Principal and Time and Rate of Interest in the correct places ; we have further solved it.
Finally when we got the amount ; to find the compound Interest ; we had to subtract Amount from principal amount.
Simple Interest :
st=P*R*T/100