Math, asked by sakshi06s7103, 9 months ago

find the amount and compound interest on 10,000 for 1 year at 10 percent p.a. compounded half year it's answer is a equals to 11,025 and Ci equals to 1,025
but I can't solve it step with statement please help me​

Answers

Answered by harshi3333
7

Answer:

Principal= Rs.10,000

Rate = 10% per annum compounded half- yearly

=) 10/2 % per half yearly

=) 5% per half yearly

Time = 1 year

Half- yearly = 2 half years

[As 1 year= 2 half years]

A/q,

Now,

Amount= Principal+ Interest

11025 = 10000+ Interest

Interest = (11025-10000)Rs.

Interest= Rs.1025

Interest when compound Annually

P=Rs.10000

R= 10%

T= 1 year

So,

Now,

Amount = Principal+ Interest

11000= 10000 + Interest

Interest= 11000- 10000

Interest= Rs.1000

this is your answer ✔️✔️

Answered by shaider
7

According to formula,

An = P( 1 +r/100)

Where A is total amount after n years, r is the rate. P is the amount initially

An =10, 000( 1 + 10/100)

=10,000( 1+0.1)"

=10,000(1.1)

An =10,000(1.1)

now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2

in the same way, A3 =10, 00(1.1)

you can see that A2/A1 = A3/A2

so, {An} is in Geometric progression.

now,

amount payable after 5years

A5 =10,000(1.1)^5

=16, 105.1 Rs

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