Question

Find the amount and compound interest on ₹10000 at rate 5 percent per annum for 3 years​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Principal (P) = Rs.10000

Time (n) = 3 years

Rate = 5%

$\sf Amount = P \bigg(1 + \dfrac{r}{100} \bigg)^{n}$

$\sf \dashrightarrow A= 10000 \times \bigg(1 + \dfrac{5}{100} \bigg)^{3}$

$\sf \dashrightarrow A= 10000 \times \bigg(\dfrac{100 + 5}{100} \bigg)^{3}$

$\sf \dashrightarrow A= 10000 \times \bigg(\dfrac{105}{100} \bigg)^{3}$

$\sf \dashrightarrow A= 10000 \times \bigg(\dfrac{21}{20} \bigg)^{3}$

$\sf \dashrightarrow A= 10000 \times \dfrac{21 \times 21 \times 21}{20 \times 20 \times 20}$

$\sf \dashrightarrow A= 10000 \times \dfrac{9261}{8000}$

$\sf \dashrightarrow A= 11576.25$

$\dashrightarrow \underline{ \boxed{ \sf \therefore Amount= Rs.11576.25 }}$

$\sf Compound \: Interest \: (CI) = Amount- Principal$

$\sf\dashrightarrow CI = 11576.35 - 10000$

$\sf\dashrightarrow CI = 11576.35 - 10000$

$\sf \dashrightarrow CI = 1576.25$

$\underline{ \boxed{ \sf \therefore Compound\: Interest= Rs.1576.25 }}$