Question

Find the amount and compound interest on 10240
for 3 years at 12 Per annum compounded annually​

Answer 1

Step-by-step explanation:

Present value= ₹ 10240 Interest rate= 12 ½ % per annum = 25/2% Time=3 years To find the amount we have the formula, Amount (A) = P (1+(R/100))n

Where P is present value, r is rate of interest, n is time in years.

Now substituting the values in above formula we get, ∴ A = 10240 (1 + (25/2)/100)3 ⇒ A = 10240 (1+1/8)3 ⇒ A = 10240 (9/8)3 ⇒ A = 31250 × 729/512 = 20 × 729 ⇒ A = ₹ 14580

∴ Compound interest = A – P = 14580 – 10240= ₹ 4340

HOPE THIS HELPS YOU ❤️

Answer 2

${\tt{\red{\underline{\underline{\huge{Question}}}}}}$

Find the amount and compound interest on 10240

for 3 years at 12 Per annum compounded annually

${\tt{\red{\underline{\underline{\huge{Answer}}}}}}$

Principle(P)=Rs.10240

Time(T)=3 years

Rate(R)=12%

Amount(A)=?

Interest (I)=?

We know

$interest = \frac{ptr}{100}$

$= \frac{10240 \times 3 \times 12}{100}$

$= \frac{399360}{100}$

$= 3993.6$

$a = p + i$

$= 10240 + 3993.6$

$= 14233.6$

Hence the interest is Rs 3993.6 and Amount is 14233.6

$\huge\boxed{\fcolorbox{red}{red}{Thank \: you}}$